编写要求:
解答:
?网友求助:
请老师帮我把分时有庄公式设成大智慧的,并做个"必买"的分时选股公式,谢谢! BTJ2:=控盘>REF(控盘,1) AND 控盘<-0.2;
源码:VAR1:=EMA(EMA(CLOSE,13),13);
控盘:=(VAR1-REF(VAR1,1))/REF(VAR1,1)*1000;
STICKLINE(控盘<0,控盘,0,1,1),COLOR00FF00;
STICKLINE(控盘>REF(控盘,1) AND 控盘<0,控盘,0,1,1),COLORFF00FF;
无庄控盘:=控盘<0;
STICKLINE(控盘>REF(控盘,1) AND 控盘>0,控盘,0,1,1),COLOR0000FF;
有庄控盘:=控盘>REF(控盘,1) AND 控盘>0;
VAR2:=100*WINNER(CLOSE*0.95);
STICKLINE(控盘0,控盘,0,1,1),COLORFFFF00;
主力出货:=控盘0;
STICKLINE(VAR2>50 AND COST(85)
高度控盘: VAR2>50 AND COST(85)
A10:=CROSS(控盘,0);
控盘B:=FILTER(IF(A10,1,0),5);
{分时价格原码}
JJ:=DYNAINFO(11);
{波段买卖原码}
P:=55;S:=8;M1:=3;
财:=(EMA(CLOSE,S)-EMA(CLOSE,P))*10,COLORRED,LINETHICK2;
神:=EMA(财,M1),COLORGREEN,LINETHICK1;
DRAWBAND(财,RGB(255,0,0),神,RGB(0,100,50));
{股价与均线偏离买卖条件}
BTJ1:=(C-JJ)/JJ<-0.005;
BTJ11:=(C-JJ)/JJ<-0.03;
BTJ12:=LAST(JJ>=REF(JJ,1),5,1) AND (C-JJ)/JJ<0.005;
STJ1:=(C-JJ)/JJ>0.005;
{控盘买卖条件}
STJ01:=控盘0.5;
STJ02:=控盘>0;
BTJ22:=控盘>REF(控盘,1) AND 控盘<0 ;
{波段买卖条件}
BTJ3:=CROSS(财,神) AND 财<-0.3;
BTJ32:=CROSS(财,神) AND 财<-0.1;
STJ31:=CROSS(神,财);
STJ32:=CROSS(神,财) AND 财>1.618;
{以下为信号};
BTJ81:=FILTER(BTJ1 AND BTJ2 AND BTJ3,13);{选股信号}
BTJ811:=FILTER(BTJ11 AND BTJ2 AND BTJ3,13);{选股信号}
BTJ82:=FILTER(BTJ12 AND BTJ22 AND BTJ32,13);{选股信号}
DRAWICON(BTJ82,神,23);{追买};
DRAWICON(BTJ81 AND TIME>10,神,27);{买底};
DRAWICON(BTJ811 AND TIME>10,神,26);{必买};
DRAWTEXT(BTJ81,神,'买底'),COLORFF00FF;
DRAWTEXT(BTJ811,神*1.2,'必买'),COLOR0000FF;
STJ81:=FILTER(STJ1 AND STJ01 AND STJ31,13);
DRAWICON(STJ81,神,19);
STJ82:=FILTER(STJ02 AND STJ32 ,13);
DRAWICON(STJ82,神,15);
STJ83:=STJ81 AND STJ82;
DRAWTEXT(STJ83,神,'必卖'),COLOR00FF00;
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