编写要求：
请老师帮忙把通达信副图“找低”指标改写成选股公式。出现“低”的位置
SJV:=FINANCE(34);{1é×ê2ú}
êDê:C/SJV,NODRAW,COLOR00FF00;
1é?°oóà?èó:=(FINANCE(1)/FINANCE(29));
êDóˉ?ê:C/FINANCE(33),NODRAW,COLORFFFF00;
DIF:=EMA(CLOSE,10)-EMA(CLOSE,22);
DE:=EMA(DIF,7.5);
MACDA:=2*(DIF-DE),;
HZL:=CROSS(MACDA,0);
LZH:=CROSS(0,MACDA);
BC:=BARSLAST(HZL OR LZH)+1;
ZGHZ:=IF(MACDA>0,HHV(MACDA,BC),0);
ZGLZ:=IF(MACDA<0,LLV(MACDA,BC),0);
DRAWBAND(ZGHZ,RGB(105,77,77),0,RGB(77,77,77));
DRAWBAND(ZGLZ,RGB(80,0,0),0,RGB(66,88,66));
DIFF:EMA(CLOSE,10)-EMA(CLOSE,22),COLORFFFFFF;
DEA:EMA(DIFF,7.5),COLOR00FFFF;
MACD:2*(DIFF-DEA), COLORSTICK,LINETHICK0;
STICKLINE(MACD>0 AND MACD>REF(MACD,1),0,MACD,1.5,1),COLORRED;
STICKLINE(MACD>0 AND MACDREF(MACD,1),0,MACD,1.5,0),COLORFFAAFF;
?ü:TROUGHBARS(3,3,1),COLOR0000FF,NODRAW;
?y:PEAKBARS(3,3,1),COLOR00FF00,NODRAW;
μí:IF(?ü=0,DIFF,IF(?y<?ü,TROUGH(3,3,1),REF(TROUGH(3,3,1),1))),COLOR00FFFF,NODRAW;
:IF(?y=0,DIFF,IF(?ü<?y,PEAK(3,3,1),REF(PEAK(3,3,1),1))),COLOR00FF00,NODRAW;
STICKLINE(?ü=0 AND DIFF<0 AND DIFF0 AND DIFF>DEA,DIFF,0,0,0),COLOR00FF00;
DRAWTEXT(?ü=0 AND DIFF<0 AND DIFF0 AND DIFF>DEA,DIFF,''),COLOR00FF00;
μíe2?:=CROSS(DIFF,DEA) AND DIFF<-0.1;
JCCOUNT:=COUNT(CROSS(DIFF,DEA),BARSLAST(DEA>=0));
?t′e2?:=CROSS(DIFF,DEA) AND DEA<0 AND COUNT(JCCOUNT=2,21)=1;
AA1:=BARSLAST(REF(CROSS(DIFF,DEA),1));
μ×±3à?:=(REF(L,AA1+1)>L OR REF(C,AA1+1)>C) AND (L,DIFF)>REF((L,DIFF),AA1+1) AND CROSS(DIFF,DEA);
DRAWLINE(AA1=0,DEA,μ×±3à?,DEA,0),COLOR0000FF,LINETHICK1;
AA2:=BARSLAST(REF(CROSS(DEA,DIFF),1));
?￥±3à?:=(REF(C,AA2+1)(H,DIFF) AND CROSS(DEA,DIFF);
DRAWLINE(AA2=0,DEA,?￥±3à?,DEA,0),COLORGREEN,LINETHICK1;
DRAWICON(CROSS(DIFF,DEA) AND DIFF>0,DEA,36);
DRAWICON(CROSS(DEA,DIFF) AND DIFF>0,DEA,37);
DRAWICON(CROSS(DIFF,DEA) AND DIFF<0,DEA,1);
DRAWICON(?t′e2?,DEA*0.9,36) ;
?a?ì1:=CONST(IF(MACD>0,1,0));
?a?ì2:=CONST(IF(MACD<0,1,0));
?a?ìA:=IF(?a?ì1=1,'a8×òDD?￡í· μ±1éò?2¨±èò?2¨ê±￡?·′oì?ùμ￡?
ò±èòD?￡¤?÷2úéúá￥±3à?ó￡?ó|°ê±3?',
IF(?a?ì2=1,'a8×òDD?￡í· μ±1éò?2¨±èò?2¨μíê±￡?
·′ì?ùμò±èòD?￡¤?÷2úéúá?μ×±3à?￡?ó|ò',
DRAWNULL));
DRAWTEXT_FIX((?a?ì1=1 OR ?a?ì2=1),0.16,0,0,?a?ìA),COLORFFEE00;
解答：
?diff:=ema(c,10)-ema(c,22);
dea:=ema(diff,7.5);
