在《完全换手2》公式中增加前数5，前量5，前数6，前量6的表达

编写要求：

以下是求助老师编写的《完全换手2》，我想在此基础上增加前数5，前量5，前数6，前量6的表达，（见附图两红线）几次编写均未成功，再次求助老师帮助，谢谢啦！ HS:V*100/FINANCE(7)*100,VOLSTICK; HS1:=INTPART(SUM(HS/100,0)); HS2:=HS1!=REF(HS1,1) OR BARSCOUNT(C)=0; HS3:=BARSLAST(HS2); HS4:=SUM(HS,HS3+1); S2:=REF(HS3,HS3+1); S3:=REF(REF(HS3,HS3+1),HS3+1); S4:=REF(REF(REF(HS3,HS3+1),HS3+1),HS3+1); Q1:=BACKSET(ISLASTBAR,HS3+1); Q2:=BACKSET(ISLASTBAR,S2+HS3+2); Q3:=BACKSET(ISLASTBAR,S3+S2+HS3+3); Q4:=BACKSET(ISLASTBAR,S4+S3+S2+HS3+4); 前数1:IF(Q1>0,BARSLAST(Q1>REF(Q1,1))+1,DRAWNULL),NODRAW,COLORYELLOW; 前量1:IF(Q1>0,SUM(HS,前数1),DRAWNULL),COLORYELLOW; 前数2:IF(Q2>0,BARSLAST(Q2>REF(Q2,1))+1,DRAWNULL),NODRAW,COLORGREEN; 前量2:IF(Q2>0,SUM(HS,前数2),DRAWNULL),COLORGREEN; 前数3:IF(Q3>0,BARSLAST(Q3>REF(Q3,1))+1,DRAWNULL),NODRAW,COLORMAGENTA; 前量3:IF(Q3>0,SUM(HS,前数3),DRAWNULL),COLORMAGENTA; 前数4:IF(Q4>0,BARSLAST(Q4>REF(Q4,1))+1,DRAWNULL),NODRAW,COLORBLUE; 前量4:IF(Q4>0,SUM(HS,前数4),DRAWNULL),COLORBLUE; STICKLINE(HS2,HS,0,2,0),COLORMAGENTA; DRAWICON(HS2,0,3); AA:=CONST(HHV(HS,120))*0.6; DRAWTEXT(CROSS(HS4,25),AA,'25％'),COLORYELLOW; DRAWTEXT(CROSS(HS4,50),AA,'50％'),COLORYELLOW; DRAWTEXT(CROSS(HS4,75),AA,'75％'),COLORYELLOW; DRAWTEXT(HS2,AA,'100％'),COLORMAGENTA; STICKLINE(CROSS(HS4,25) OR CROSS(HS4,50) OR CROSS(HS4,75),HS,0,0,0),COLORYELLOW; DRAWTEXT(Q1>REF(Q1,1),AA/2,'1次'),COLORYELLOW; DRAWTEXT(Q2>REF(Q2,1),AA/2,'2次'),COLORGREEN; DRAWTEXT(Q3>REF(Q3,1),AA/2,'3次'),COLORMAGENTA; DRAWTEXT(Q4>REF(Q4,1),AA/2,'4次'),COLORBLUE;

解答：

?Q2:=BACKSET(ISLASTBAR,S2+HS3+2);

Q3:=BACKSET(ISLASTBAR,S3+S2+HS3+3);